(3x^2-24x^2)/32=0

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Solution for (3x^2-24x^2)/32=0 equation: 



(3x^2-24x^2)/32=0

We multiply all the terms by the denominator


(3x^2-24x^2)=0

We get rid of parentheses

3x^2-24x^2=0

We add all the numbers together, and all the variables

-21x^2=0

a = -21; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-21)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-42}=0$

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